April 13, 2006 by Vurdlak
Try to figure this one out! How is it possible that two is equal to one, when we all know that that isn’t true. Try to spot the mistake one of the twins made!
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WOW….
barring the possibility that there are little kids posting…
if you are an adult and have gone through the education system and don’t understand the simple math like the connection between a=b and a^2=a*b you shouldn’t be allowed to have kids.
Sorry about being harsh, because its fine to be stumped by this, its not ok to not know basic elementary school math
so really the solution is 2/0 = 1/0 ?
And that is true…
So the real “mistake” is saying that 2/0 = 2 and that 1/0 = 1….
And if anyone reads this far down, get a f’in life
this is not an optical illusion,they just try to confuse you and check if you at lest remmember 6grade maths.everything that’s below line 3 is not right:
(a+b)(a-b) will never equale the statement b(a-b)
always (a+b)(a-b)=a2+b2
There is a missing condition fot divison (as you all mentioned)
-> a-b /= 0 =>
-> a /= b
which it isn't, there for you can't
the mistake is in the transition from the fourth to the fifth line whereby the (a-b) on both sides is ‘cancelled’. Remembering that anything divided by 0 is undefined, divividing both sides by a-b which is really zero simply means that undefined = undefined. WOOP DE DOO. =.= , back to the drawing board.
wow some of u r in 8th grade and u cant even figure this out… and some of you have no humour, some of you think it’s a set of unrelated equations… i found the error when i was in 6th grade! and the error is that you cant divide by zero.
(a+b)=b
not true^^^
got me for a minute tho, hadda think it throughht
and comment #1… (mark)
are you saying 8th grade math is easy
cause im in 8th grade, and im taking an advanced course, and its still hard
it should come out to be 0=0
because (a+b)(a-b)=b(a-b) equals zero
and 2a=a which is the same as 0+0=0
should in fact be
0=0
so the only way the whole equation..or however they are trying to figure this out works is to ultimately say a and b equal zero. so every equation they wrote satisfys that. so 2a=a –> 2(0)=0! and (a+b)=b –> (0+0)=0!
so the only mistake they made is at the end when they assumed that a and b were 1.
so in lines 4 and 5 to say that they were dividing by zero so that doesn't work is stupid because they were writting random equations not following steps to get to the next problem duh :P
You can divide by zero in calculus though with L’Hospitals rule, ha ha
They missed out the parameters - "a=b=1" (or if you prefer "a=1", "b=12)
Need to state what a & b are ;) otherwise it is technically correct and then the last line is also wrong… you cant just assume 'a' is equal to one - needs to be stated… yes, im a uni student with nothing better to do ;)
“this is not an optical illusion,they just try to confuse you and check if you at lest remmember 6grade maths.everything that’s below line 3 is not right:
(a+b)(a-b) will never equale the statement b(a-b)
always (a+b)(a-b)=a2+b2″
First of all this must be corrected:
“always (a+b)(a-b)=a2+b2″
should read:
“always (a+b)(a-b)=a^2-b^2″
In this situation, this isn’t the error.
b(a-b) is equal to ab-b^2 and since a=b this could also read a^2-b^2.
The real error is as it has been said before, when they divide by zero by trying to cancel by dividing the (a-b) over since a=b, a-b = 0. You cannot divide by zero.
if a=b , then a and b are equal, meaning that THEY ARE THE SAME NUMBER!
therefore, the answer cant be 2=1
Don’t blame me for not getting this i’m still in primary school…(age 11) tho some of my classmates have that a - b = ? some sort of things…